badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

A stone is thrown vertically up from the top of a tower with some initial velocity and it arrives on the ground after t1t1 seconds. Now if the same the stone is thrown vertically down from the top of the same tower with the same initial velocity, it arrives on ground after t2t2 seconds. In how much time will the stone take to reach the ground if it is dropped from the same tower?

2 years ago

Answers : (1)

Arun
24742 Points
							

Displacement of Stone 1 in time t1 (h) = ut1 – g(t1)2/2
Displacement of Stone 2 in time t2 (h) = ut2 + g(t2)2/2
Displacement of Stone 2 in time t3 (h) = g(t3)2/2

calculate u from the equation 2 and substitute in 1.
calculate h from eq. 3 and substitute in the above derived equation by rearranging and factoring we get (t3)^2 = t1t2

 

Regards,

Arun (AskIITians Forum Expert)

2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 18 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details