0

Guest

Courses New

A stone is thrown vertically up from the top of a tower with some initial velocity and it arrives on the ground after t1t1 seconds. Now if the same the stone is thrown vertically down from the top of the same tower with the same initial velocity, it arrives on ground after t2t2 seconds. In how much time will the stone take to reach the ground if it is dropped from the same tower?

A stone is thrown vertically up from the top of a tower with some initial velocity and it arrives on the ground after t1t1 seconds. Now if the same the stone is thrown vertically down from the top of the same tower with the same initial velocity, it arrives on ground after t2t2 seconds. In how much time will the stone take to reach the ground if it is dropped from the same tower?

Grade:11

1 Answers

Arun
25750 Points
6 years ago

Displacement of Stone 1 in time t1 (h) = ut1 – g(t1)2/2
Displacement of Stone 2 in time t2 (h) = ut2 + g(t2)2/2
Displacement of Stone 2 in time t3 (h) = g(t3)2/2

calculate u from the equation 2 and substitute in 1.
calculate h from eq. 3 and substitute in the above derived equation by rearranging and factoring we get (t3)^2 = t1t2

 

Regards,

Arun (AskIITians Forum Expert)

Think You Can Provide A Better Answer ?

Other Related Questions on General Physics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More