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`        A stone is dropped from the top of the tower of height 60m.Simultaneously another stone is projected vertically upwards from the foot of the tower .They meet at a height 2h/3 from the ground level .The initial velocity of the stone projected upwards is `
11 months ago

Saurabh Koranglekar
6402 Points
```							Dear studentTime by upper stone to cover h/3 = 20 m is 2 secTime by lower stone to cover 40 m = 2 secFinding initial velocity40 = 2u - 0.5*10*2*260/ 2 = 30 m/s = uu = 30 m/sRegards
```
10 months ago
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