A stone is dropped from the top of the tower of height 60m.Simultaneously another stone is projected vertically upwards from the foot of the tower .They meet at a height 2h/3 from the ground level .The initial velocity of the stone projected upwards is

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Saurabh Koranglekar · Answer

Dear student Time by upper stone to cover h/3 = 20 m is 2 sec Time by lower stone to cover 40 m = 2 sec Finding initial velocity 40 = 2u - 0.5*10*2*2 60/ 2 = 30 m/s = u u = 30 m/s Regards

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A stone is dropped from the top of the tower of height 60m.Simultaneously another stone is projected vertically upwards from the foot of the tower .They meet at a height 2h/3 from the ground level .The initial velocity of the stone projected upwards is

A stone is dropped from the top of the tower of height 60m.Simultaneously another stone is projected vertically upwards from the foot of the tower .They meet at a height 2h/3 from the ground level .The initial velocity of the stone projected upwards is

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A stone is dropped from the top of the tower of height 60m.Simultaneously another stone is projected vertically upwards from the foot of the tower .They meet at a height 2h/3 from the ground level .The initial velocity of the stone projected upwards is

A stone is dropped from the top of the tower of height 60m.Simultaneously another stone is projected vertically upwards from the foot of the tower .They meet at a height 2h/3 from the ground level .The initial velocity of the stone projected upwards is

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