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A stone after falling freely under the influence of gravity for 1s strikes a glass plate held horizontally. In breaking through the glass plate, the stone losses half the velocity. How far will it travel in next 2s? A stone after falling freely under the influence of gravity for 1s strikes a glass plate held horizontally. In breaking through the glass plate, the stone losses half the velocity. How far will it travel in next 2s?
We know that,v=u+atIn here,u/2=g, i.t u=2gNow, s=ut+1/2at2 =2x2g+5x4 =60mSo, the stone will move 60m in the next 2s is 60
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