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Grade: 11
        
A stable body of mass 4m explodes into three parts.if two parts of mass mmoves with velocity v perpendicularly then find out velocity of the third part of mass 2m.find out the increase in kinetic energy after explosion.(solve by explaining each step)..
6 months ago

Answers : (1)

Khimraj
2873 Points
							
as external force is zero so momentum will be conserved.
0 = mv \hat{i} + mv \hat{j} + 2mx
so x = -(\hat{i}+\hat{j})v/2
magnitude of velocity = v/\sqrt{2}
increse in KE = 2*½*m*v2 + ½*2m*(v2/2) = 3mv2/2
Hope it clears..........................
6 months ago
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