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        A stable body of mass 4m explodes into three parts.if two parts of mass mmoves with velocity v perpendicularly then find out velocity of the third part of mass 2m.find out the increase in kinetic energy after explosion.(solve by explaining each step)..
9 months ago

Khimraj
3008 Points
							as external force is zero so momentum will be conserved.0 = mv $\hat{i}$ + mv $\hat{j}$ + 2mxso x = -($\hat{i}$+$\hat{j}$)v/2magnitude of velocity = v/$\sqrt{2}$increse in KE = 2*½*m*v2 + ½*2m*(v2/2) = 3mv2/2Hope it clears..........................

9 months ago
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• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions