0

Guest

Courses New

A stable body of mass 4m explodes into three parts.if two parts of mass mmoves with velocity v perpendicularly then find out velocity of the third part of mass 2m.find out the increase in kinetic energy after explosion.(solve by explaining each step)..

A stable body of mass 4m explodes into three parts.if two parts of mass mmoves with velocity v perpendicularly then find out velocity of the third part of mass 2m.find out the increase in kinetic energy after explosion.(solve by explaining each step)..

Grade:11

1 Answers

Khimraj
3007 Points
5 years ago
as external force is zero so momentum will be conserved.
0 = mv \hat{i} + mv \hat{j} + 2mx
so x = -(\hat{i}+\hat{j})v/2
magnitude of velocity = v/\sqrt{2}
increse in KE = 2*½*m*v2 + ½*2m*(v2/2) = 3mv2/2
Hope it clears..........................

Think You Can Provide A Better Answer ?

Other Related Questions on General Physics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More