MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        A spy report about a suspected car reads as follows. “The car moved 2∙00 km towards east, made a perpendicular left turn, ran for 500m, made a perpendicular right turn, ran for 4∙00 km and stopped”. Find the displacement of the car. 
4 years ago

Answers : (1)

Aditi Chauhan
askIITians Faculty
396 Points
							Sol. (AD) ⃗ 2i ̂  + 0.5 j ̂ + 4 K ̂ = 6i ̂ + 0.5 j ̂
AD = √(AE^2+DE^2 ) = 6.02 KM
Tan θ = DE / AE = 1/12
Θ = tan 1 (1/12)
The displacement of the car is 6.02 km along the distance tan-1 (1/12) with positive x-axis. 

						
4 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 18 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details