Grade 12th passGeneral Physics

A spring of constant K is cut into two parts by the ratio of length 1:2 . The spring constant of larger one is?

Muskan Fatima

9 Years agoGrade 12th pass

1 Answer

Vikas TU

9 Years ago

Dear Student,

From the given data, proportion of spring constants of the two spring sections = 2:1

What's more, we likewise know the way that the bigger section will have littler spring steady.

So for this , we can expect the qualities to be 2x and x. At the point when these two are in arrangement, they offer ascent to the first spring. So

2x * x/(2x + x) = k

which gives x = 3k/2.

So spring constants are 3k/2 and 3k.

When they are in parallel, successful spring consistent = 3k + 3k/2 = 9k/2

Era T = 2*pi sqrt (2m/9k).

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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A spring of constant K is cut into two parts by the ratio of length 1:2 . The spring constant of larger one is?

Muskan Fatima

1 Answer

Vikas TU

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