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Spring potential Es energy is defined as,
Es = ½ kx2
Here k is the spring constant or stiffness constant and x is the compression or elongation.
In equilibrium, EK = Es
=½ kx2
So, compression, x = v[2 EK/k]
Substitute, 7 J for EK and 10 N/m for stiffness constant k in the equation x = v[2 EK/k], we get,
x = v[2 EK/k]
=v[2(7J)/(10 N/m)]
= 1.18 m
Rounding up to one significant figure, the maximum compression of the spring will be 1 m.
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