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Grade 11General Physics

A source emits 45 joules of energy in 15sec. What is the radiant flux of the source?

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12 Years agoGrade 11
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1 Answer

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ApprovedApproved Tutor Answer1 Year ago

To determine the radiant flux of a source that emits energy, we can use a straightforward formula. Radiant flux, often referred to as power in the context of energy emission, is calculated by dividing the total energy emitted by the time over which it is emitted. In this case, we have a source emitting 45 joules of energy over a period of 15 seconds.

Calculating Radiant Flux

The formula for radiant flux (Φ) is:

Φ = E / t

Where:

  • Φ is the radiant flux in watts (W)
  • E is the energy emitted in joules (J)
  • t is the time in seconds (s)

Plugging in the Values

Now, let’s substitute the values we have:

E = 45 J

t = 15 s

Using the formula:

Φ = 45 J / 15 s

Performing the Calculation

Now, we simply perform the division:

Φ = 3 W

Understanding the Result

The radiant flux of the source is 3 watts. This means that the source emits energy at a rate of 3 joules per second. To put this in perspective, if you think of radiant flux as a flow of energy, it’s like a water faucet: the more you turn it on, the more water (or energy, in this case) flows out per second.

In practical terms, this concept is crucial in fields like physics and engineering, where understanding how much energy is emitted or transferred over time can influence design and efficiency in systems ranging from light bulbs to solar panels.