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A soap bubble of radius r is placed on another bubble of radius 2r. The radius of the surface common to both the bubbles is ?please explain.

satyam sahu , 8 Years ago
Grade 12th pass
anser 1 Answers
Vikas TU

Last Activity: 8 Years ago

Total Pressure exerted when small bubble lies on another big bubble = > 
let r’ be its radii then,
4T/r’ = 4T/r – 4T/2r
solving r and r’ we get,
r’ = 2r hence.

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