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Grade 12General Physics

A simple microscope is rated 5 X for a normal relaxed eye.What will be its magnifying power for a relaxed farsighted eye whose near eye point is 40cm

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12 Years agoGrade 12
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ApprovedApproved Tutor Answer0 Years ago

To determine the magnifying power of a simple microscope for a relaxed farsighted eye, we need to understand how the eye's near point affects the overall magnification. A simple microscope typically magnifies an object by allowing the eye to see it closer than its near point. For a normal relaxed eye, this near point is about 25 cm. However, in your case, the near point is 40 cm, which means the eye has a different capacity for focusing on close objects.

Understanding Magnifying Power

The magnifying power (M) of a simple microscope can be calculated using the formula:

  • M = D / F

Where:

  • D is the least distance of distinct vision (the near point) for the eye.
  • F is the focal length of the lens used in the microscope.

Applying the Formula

For a normal relaxed eye, the least distance of distinct vision (D) is approximately 25 cm. In your case, the relaxed farsighted eye has a near point of 40 cm. The focal length (F) of the simple microscope is determined by its magnification rating. Since the microscope is rated at 5X, we can assume that it allows the user to see an object at a distance closer than the near point of a normal eye.

To find the effective magnifying power for the relaxed farsighted eye, we need to adjust the formula:

  • M = D' / F

Here, D' is the near point for the relaxed farsighted eye, which is 40 cm. We need to find the focal length (F) based on the original magnification of 5X.

Calculating Focal Length

For the normal eye:

  • Using the original magnifying power: M = 5 = 25 cm / F

From this, we can rearrange to find F:

  • F = 25 cm / 5 = 5 cm

Finding the New Magnifying Power

Now that we have the focal length (F = 5 cm), we can substitute this back into our adjusted magnifying power formula for the relaxed farsighted eye:

  • M = D' / F = 40 cm / 5 cm = 8

Final Result

Therefore, the magnifying power of the simple microscope for a relaxed farsighted eye whose near point is 40 cm is 8X. This means that the microscope will appear to magnify objects 8 times larger than they would appear to the eye at its near point.

This example illustrates how the characteristics of the eye can significantly influence the effectiveness of optical instruments like microscopes. Understanding these relationships helps in optimizing the use of such devices for individuals with varying vision capabilities.