Grade 12th passGeneral Physics

A shell is fired vertically upwards with a velocity v1 from trolley moving horizontally with velocity v2 .a person on the ground observes the motion of the shell as a parabola , whose horizontal range is

Tripti sharma

8 Years agoGrade 12th pass

2 Answers

Arun

8 Years ago

Horizontal range equals:
x = V2 *t
where t is of motion.
Time of motion can be found from (object moving if his height >0) :
ℎ = V1*t −
1/2* g* t^2 = 0
Therefore, time of motion equals:
t = 2*V1/g

Finally, horizontal range equals:
x = V2*t = 2 V1* V2/g

Abhay

7 Years ago

Horizontal range =v^2sin2theta/g

So,

We can write the above equations as ,

Range =2(vsin theta)(vcos theta)/g

Here ,as you can see (vsin theta )=vertical velocity

And........ (vcos theta)=horizontal velocity.

And ,vertical velocity =v1

Horizontal velocity =v2

So put these velocities in the horizontal range equation

The final answer is 2v1v2/g.

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A shell is fired vertically upwards with a velocity v1 from trolley moving horizontally with velocity v2 .a person on the ground observes the motion of the shell as a parabola , whose horizontal range is

Tripti sharma

2 Answers

Arun

Abhay

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