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A semiconductor has equal electron and hole concentration of 6 x 108 /m3 . On doping with certain impurity, electron concentration increases to 9 X1012 /m3 . (i) Identify the new semiconductor obtained after doping. (ii) Calculate the new hole concentration. ?

tanisha singh , 12 Years ago
Grade 11
anser 1 Answers
Saurabh Koranglekar
Dear student

The answer is n type as e concentration is more

new hole conc will be governed by formula
ni^2 / ne = np;

Regards
Last Activity: 5 Years ago
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