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A rotating table completes one rotation is 10 sec. and its moment of ineratia is 100 kg-m2. A person of 50 kg. mass stands at the centre of the rotating table. If the person moves 2m. from the centre, the angular velocity of the rotating table in rad/ sec. will be:

A rotating table completes one rotation is 10 sec. and its moment of ineratia is 100 kg-m2. A person of 50 kg. mass stands at the centre of the rotating table. If the person moves 2m. from the centre, the angular velocity of the rotating table in rad/ sec. will be:

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Grade:12th pass

1 Answers

Vikas TU
14149 Points
7 years ago
Net torqe about the centre of rotation is zero hence angular monetum is conserved here.
Therfore, I1w1 = I2w2
100*(2pi/10) =(100 + 50*4)*w
20pi = 300w2
w2 = 2pi/30 => pi/15 rad/s

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