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`        A rotating table completes one rotation is 10 sec. and its moment of ineratia is 100 kg-m2. A person of 50 kg. mass stands at the centre of the rotating table. If the person moves 2m. from the centre, the angular velocity of the rotating table in rad/ sec. will be:`
3 years ago

Vikas TU
9794 Points
```							Net torqe about the centre of rotation is zero hence angular monetum is conserved here.Therfore, I1w1 = I2w2100*(2pi/10) =(100 + 50*4)*w20pi = 300w2w2 = 2pi/30 => pi/15 rad/s
```
2 years ago
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• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions