Grade 12Mechanics

A rigid ball of mass m strikes a rigid wall at 60 degree and gets reflected without any loss of speed. The value of impulse imparted by the wall on the ball will be ?

mv

2mv

mv/2

mv/3

Abina George

9 Years agoGrade 12

3 Answers

Vikas TU

9 Years ago

Dear Student,
After doing components,

v1= v X root3/2 i^ - v X root3/2 j^
v2= - v X root3/2 i^ - v X root3/2 j^

Impulse on wall = mv1 – mv2
=m root3 x v.

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

SUBHAM GHOSH

7 Years ago

Impulse = F × ∆t

Now , F = (ma)

F = { m(v2 - v1)/ ∆t }

Impulse = m(v2 - v1)

v1 = v cos 60° (i^) + v sin 60° (- j^)

v2 = v cos 60° (- i^) + v sin 60° (- j^)

Impulse = m × ( v2- v1 )

= m × 2v cos60° (- i^)

= m × 2v × ( 1/2) (- i^)

= mv (- i^)

Kushagra Madhukar

5 Years ago

Dear student,

Please find the attached solution to your problem.

As we know, angle of incidence = angle of reflection.

Now, v₁ = v cos 60° i + v sin 60° j [ where, v is the speed of ball]

Hence, velocity after reflection,

v₂ = – v cos 60° i + v sin 60° j

Now, by impulse momentum theorem we have,

Impulse = change in momentum

= mv2 – mv1

= m( – 2v cos 60^o i ) = – mv i

Hence, magnitude of impulse = mv

Hope it helps.

Thanks and regards,

Kushagra

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A rigid ball of mass m strikes a rigid wall at 60 degree and gets reflected without any loss of speed. The value of impulse imparted by the wall on the ball will be ? mv 2mv mv/2 mv/3

Abina George

3 Answers

Vikas TU

SUBHAM GHOSH

Kushagra Madhukar

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A rigid ball of mass m strikes a rigid wall at 60 degree and gets reflected without any loss of speed. The value of impulse imparted by the wall on the ball will be ?

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