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a projectile is aimed at a tall gate on the horizontal plane and falls 12 meter short when the angle of projection is 15 while it over shoots by 24 meters when the angle is 45 find the angle of projection to hit the angle
a projectile is aimed at a tall gate on the horizontal plane and falls 12 meter short when the angle of projection is 15 while it over shoots by 24 meters when the angle is 45 find the angle of projection to hit the angle

```
3 years ago

Arun
25768 Points
```							R’ is the required range = [u²/g] sin 2θ When θ = 15° R(15) = [u²/g] sin 30 = R’ – 12 where R’ is the required range .-----1 When θ = 45° R(45) = [u²/g] sin 45 = R’ + 24 where R’ is the required range ---2. 2-1gives 0.207[u²/g] = 36 [u²/g] = 173.9130 Substituting in 1 [u²/g] sin 30 = R’ – 12 173.9130* sin 30 = 173.9130 sin 2θ - 12 sin 2θ = 0.569 θ = 17.34° or 72.76° For these two angles the projectile will reach the mark.
```
3 years ago
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