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`        A pot of mass 1kg is raised vertically at a constant velocity with both the hands. The coefficient of friction between hand and pot is 0.2 .What is the force applied by each hand?`
one year ago

Vikas TU
11137 Points
```							Let the normal force exerted by one hand be x.Then, frictional force = 2x × 0.2 =0.4xAs, velocity is constant ; therefore net force is zero.So, weight of pot is equal to frictional force.: 0.4x = 9.8x= *24.5 N
```
7 months ago
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