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Grade: 11

                        

a particle starts to move from rest along X axis with an acceleration of 2m/s 2 after 4 sec its acceleration is also towards -ve y axis of 2m/s 2 what will be its quadrant after 8 sec's?

4 years ago

Answers : (1)

Vikas TU
13786 Points
							
at 4 seconds,
v = 0 + 2*4icap => 8 icap
after then,
v2 = 8  icap – 2jcap *8 => 8icap -16jcap
angle = arctan(-16/8) = arctan(-2) = – 64.3 degree.
that is in fourth quadrant. 
 
4 years ago
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