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A particle starts moving with acceleration 2 ms-2 . distance travelled by it in the fifth half-second is:1)1.25m2)2.25m3)6.25m4)30.25m

anirban deb , 10 Years ago
Grade 11
anser 2 Answers
bharat bajaj

Last Activity: 10 Years ago

Distance travelled in fifth half second = Distance travelled in 5/2 seconds - Distance travelled in 2 seconds...s = 1/2. 2 . (5/2)^2 = 1/2.2.(2)^2 = 25/4 - 4 = 6.25 - 4 = 2.25 m..Option 2) is correct...THanks

Bharat BajajIIT Delhi
askiitians faculty

Arun Kumar

Last Activity: 10 Years ago

Hello
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty

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