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Grade: 11
        
A particle starts moving with acceleration 2 ms-2 . distance travelled by it in the fifth half-second is:
1)1.25m
2)2.25m
3)6.25m
4)30.25m
5 years ago

Answers : (2)

bharat bajaj
IIT Delhi
askIITians Faculty
122 Points
							Distance travelled in fifth half second = Distance travelled in 5/2 seconds - Distance travelled in 2 seconds...s = 1/2. 2 . (5/2)^2 = 1/2.2.(2)^2 = 25/4 - 4 = 6.25 - 4 = 2.25 m..Option 2) is correct...THanks
Bharat BajajIIT Delhi
askiitians faculty
5 years ago
Arun Kumar
IIT Delhi
askIITians Faculty
256 Points
							
Hello
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty
5 years ago
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