badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

A particle starts from rest and moves on a curve with constant angular acceleration of 3.0 rad/s square units .An observer starts his stopwatch at a certain instant and record that the particle covers an angular span of 120 rad at the end of 4th second.How long had the particle moved when the observer started his stopwatch?

4 years ago

Answers : (3)

Kuldeep Pal
53 Points
							
Let The total displacement be when stpwatch starts be “X”
so, the total displacent =
   X=0.t + (1/2).3.4.4
   X=12rad.
 
So. The Angular displacement when the stopwatch starts=
   X= (1/2).3.T2 _______(1)
And Also it is given that total time is 4s and Total Angular Displacent is 12rad. 
So,    12-X=(1/2).3(4-T)2 ______(2)
Hence Two equations And two unknown , We Can Find ‘T’ and ‘X’.
4 years ago
Leaf
10 Points
							
I don’t think that’?s right.I’l?l try making the question more clear.The 4th    ?second is 4 seconds after the stopwatch was started and the total displacement was 120 rad throughout its entire motion.We’ re supposed to find the amount of time it travelled until the observer started his stopwatch.
4 years ago
Kuldeep Pal
53 Points
							
Whats problem in this ..This is more simpler than previous one.
The Angular displacent in ‘n’th second is given by:
     (X)n = u + (a/2)(2n-1)
     Where, u = the angular velocity when the stopwatch start.
                 a = The Angular Acceleration of The Motion.
                 n = ‘n’th second.
  So,    120 = u + (3/2)(7)
            u = 219/2.
        Hence , We have The Angular velocity when Stopwatch Starts.
   And By,   v2 = u2 + 2aX. we Can find the angular Displacement.
                 {(219/2)2 -(0)2}/2.3 = X
  The Method Is right.
4 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 18 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details