Create your Smart Home App in the Free Webinar on Home Automation. Register Now
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Free webinar on App Development Learn to create your own Smart Home App
16th Jan @ 5:00PM for Grade 1 to 10
Sit and relax as our customer representative will contact you within 1 business day
A particle starts from rest accelarates 2m/s2 for 10 s and then goes at constant speed for 30 s and tgen deaccelarates at 4m/s2 till it stops. What is distance covered by it
First of all.Applying s=ut+1/2at² we get s=100mSecondly we calculate the final velocity by that time by applying the formula v=u+at. v comes to be 20m/s.Now since now there is movement with constant speed hence now applying d=s×t we get d=600m.Now since there is deacceleration so the final velocity will be 0 so using the formula v=u-at we get t=5 sec for the body to stop.Now again applying the formula s=ut-1/2at² we get the distance to be 50m.Hence finally the total distance covered by it will be 750m.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -