A particle of mass m moving with a speed v hits elastically another stationery particle of masss 2m in a fixed smooth horizontal circular tube of radius r.Find the time when the next collision will take place?

Question

d s sahu · Answer

Relative velocity of approach =relative velocity of separation = v (since e=1).Therefore, time taken= 2πr/v

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A particle of mass m moving with a speed v hits elastically another stationery particle of masss 2m in a fixed smooth horizontal circular tube of radius r.Find the time when the next collision will take place?

A particle of mass m moving with a speed v hits elastically another stationery particle of masss 2m in a fixed smooth horizontal circular tube of radius r.Find the time when the next collision will take place?

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A particle of mass m moving with a speed v hits elastically another stationery particle of masss 2m in a fixed smooth horizontal circular tube of radius r.Find the time when the next collision will take place?

A particle of mass m moving with a speed v hits elastically another stationery particle of masss 2m in a fixed smooth horizontal circular tube of radius r.Find the time when the next collision will take place?

1 Answers

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