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Grade 12th passGeneral Physics

A particle of mass m collides on a rod of mass m = M and length l at one end with velocity V normal to its length . After collision the particle stick to it . if the system is on a smooth horizontal surface , The angular velocity of the combined mass immediately after the collision

Profile image of Chanchal
10 Years agoGrade 12th pass
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1 Answer

Profile image of Vikas TU
10 Years ago
since net torque on system is zero, angular momentum is conserved for the system.
therefore,
mvl/2 + 0 = mwl^2/2 + (Ml^2/3 + ml^2)w 
caluclate w from the eqn.