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A particle moving with a non zero velocityand constant acceleration on straightline travels 15m in first 3s and 33m in next 3s in the same direction find initial velocity and acceleration of particle.
Dear Varsha using the eq _-- s= ut +1/2 a t^215=3u+9/2a----5=u+3/2a ........1next 33 m in 3s,tot dist=15+33=48tot tme=3+3=648=6u+18a--- 8=u+3a.......2equating both we get,3=3/2a == a = 2m/s^2u=2m/s.....
using the eq _-- s= ut +1/2 a t^2
15=3u+9/2a----5=u+3/2a ........1
next 33 m in 3s,
tot dist=15+33=48
tot tme=3+3=6
48=6u+18a--- 8=u+3a.......2
equating both we get,
3=3/2a == a = 2m/s^2
u=2m/s.....
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