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A particle moves with a constant velocity parallel to the X-axis. Its angular momentum with respect to the origin

priya , 12 Years ago
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Askiitians Tutor Team

When we talk about a particle moving with a constant velocity parallel to the X-axis, we can analyze its angular momentum with respect to the origin using some fundamental concepts from physics. Angular momentum is a measure of the rotational motion of an object and is dependent on both the linear momentum of the particle and its position relative to a chosen point, in this case, the origin.

Understanding Angular Momentum

Angular momentum (L) can be defined mathematically as:

  • L = r × p

Here, r is the position vector from the origin to the particle, and p is the linear momentum of the particle. The linear momentum is given by:

  • p = mv

where m is the mass of the particle and v is its velocity.

Position Vector and Velocity

For a particle moving parallel to the X-axis, we can express its position vector r as:

  • r = (x, 0, 0)

Here, x is the position along the X-axis, and the Y and Z components are zero since the motion is purely horizontal. If the particle has a constant velocity v in the X direction, we can write:

  • v = (v, 0, 0)

Calculating Angular Momentum

Now, substituting the expressions for r and p into the angular momentum formula:

  • L = r × p = (x, 0, 0) × (mv, 0, 0)

To compute the cross product, we can use the determinant of a matrix:

  • L = |i j k|
  • |x 0 0|
  • |mv 0 0|

Calculating this determinant, we find:

  • L = (0 - 0)i - (0 - 0)j + (x * mv - 0)k

This simplifies to:

  • L = 0i + 0j + (x * mv)k

Thus, the angular momentum is:

  • L = xmv k

Key Insights

This result shows that the angular momentum of the particle with respect to the origin is dependent on its position along the X-axis (x), its mass (m), and its velocity (v). The angular momentum vector points in the Z direction, indicating that the particle's motion around the origin is in the plane perpendicular to the X-axis.

In summary, while the particle moves with a constant velocity parallel to the X-axis, its angular momentum is not zero unless it passes through the origin (where x = 0). This illustrates how angular momentum is influenced by both the position and the linear momentum of the particle, providing a deeper understanding of its motion in a rotational context.

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