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let total distance of path is S ...
for first half , time taken if t
speed = distance/time
3 = S/2t
t = S/6 .............1
for second half , time taken is T ...
for first T/2 it moves with 4.5
4.5 = 2x/T
x = 4.5T/2 ...........2
for second T/2 it moves with 7.5
7.5 = 2y/T
y = 7.5T/2 ..........3
we have , x+y = S/2so
(7.5+4.5)T = S/2
T = S/24 ...............4
total time taken during its motion is T+t
Ttotal = T+t = S/24+S/6 = 5S/24
total distance = S
average speed = total distance/total time = S/5S/24 = 24/5 = 4.8m/s
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