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Grade 12th passGeneral Physics

A particle moves in a circle of radius 20 cm. Its linear speed is given by v=2t, where t is in second and v is in m/s. Find the radial and tangential acceleration at t= 3s .

raghav

11 Years agoGrade 12th pass

2 Answers

Apoorva Arora

11 Years ago

The linear speed at t= 3 s is

$v= 2t = 6 m/s.$

The radial acceleration at t= 3 s is

$a_{r} = v^{2}/r = \frac{36 m^{2}/s^{2}}{0.20 m} = 180 m/s^{2}.$

The tangential acceleration is

$a_{t} = \frac{\mathrm{d} v}{\mathrm{d} t} = \frac{\mathrm{d} (2t)}{\mathrm{d} t} = 2 m/s^{2}.$

Kushagra Madhukar

6 Years ago

Dear student,

Please find the attached solution to your question.

at time, t = 3s

Linear speed, v = 2t = 2 x 3 = 6m/s

radial acceleration, a_r = v²/r = 6²/0.2 = 36/0.2 = 180m/s²

Tangential acceleration, a_t = dv/dt = d(2t)/dt = 2m/s²

Hope it helps.

Thanks and regards,

Kushagra

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