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A PARTICLE MOVES ALONG THE SIDE AB , BC AND CD , OF A SQUARE OF SIDE 25 M WITH A VELOCITY OF 15 M/S . ITS AVERAGE SPEED IS ?

RIYA SHAHANA , 8 Years ago
Grade 11
anser 1 Answers
Ankit Jaiswal

Last Activity: 8 Years ago

Average speed is = distance / timetotal distance = 25 x 3 = 75m total time = 3 x (25/15) = 5shence average speed = 75/5 = 15m/sI hope this helps

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