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A particle moves along the parabolic path x=y2 + 2y + 2 in such a way that the y component of velocity vector remains 5m/s during the motion. The magnitude of the acceleration of the particle is?
x = y2 + 2y +2differentiating wrt timevx = 2yvy + 2vyagain differentiating wrt timeax= 2vy2 + 2yay + 2ayay = 0 as vy = 5m/s(constant)then ax = 2*52 = 50 m/s2So a = = 50m/s2Hope it clears.
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