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A particle moves along a circle of radius R with a constant angular speed omega .Its displacement(only magnitude)in time t will be

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Arun

Last Activity: 6 Years ago

Consider and to be the initial and final positions. Using simple trigonometric relations we can obtain the shortest distance or the Displacement between and by the following equation -

AB = 2Rsin(theta/2)

Here,

R= radius of circle

theta= the angular displacement = w*T

w= angular speed

T= time taken

So, |AB| = 2Rsin(w*T/2)

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