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A particle moves along a circle of radius R with a constant angular speed omega .Its displacement(only magnitude)in time t will be
Consider A and B to be the initial and final positions. Using simple trigonometric relations we can obtain the shortest distance or the Displacement between A and B by the following equation -AB = 2Rsin(theta/2)Here,R= radius of circletheta= the angular displacement = w*Tw= angular speedT= time takenSo, |AB| = 2Rsin(w*T/2)
Consider A and B to be the initial and final positions. Using simple trigonometric relations we can obtain the shortest distance or the Displacement between A and B by the following equation -
AB = 2Rsin(theta/2)
Here,
R= radius of circle
theta= the angular displacement = w*T
w= angular speed
T= time taken
So, |AB| = 2Rsin(w*T/2)
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