a particle moves a distance x in time t according to equation x=(t+5)^-1,the acceleration of the particle is proportional tovelocity^3/2\tdistance^2\tdistance^-2\tvelocity^2/3
RATNAPRIYA MISHRA , 8 Years ago
Grade 12th pass
1 Answers
Vikas TU
Last Activity: 8 Years ago
accleration = duble differentiation of displacemnt w.r.t time.
Hence,
dx/dt = -(t+5)^-2 = v
d2x/dt^2 = 2(t+5)-3 = a
subsitute v in a and get the answer.
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