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a particle moves a distance x in time t according to equation x=(t+5)^-1,the acceleration of the particle is proportional to velocity^3/2 distance^2 distance^-2 velocity^2/3
accleration = duble differentiation of displacemnt w.r.t time.Hence,dx/dt = -(t+5)^-2 = vd2x/dt^2 = 2(t+5)-3 = asubsitute v in a and get the answer.
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