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A particle is suspended from a fixed point and projected horizontally with velocity √7gl/2.the string will slack through an angle find that angle.
in y direction from neton’s thord law of eqn.,(vy)^2 = (√7gl/2)sinthetha – 0.5gt^2and(vx)^2 = (√7gl/2)costhetha – gtNow put vx and vy = 0 and solve for thetha and t.
A particle suspend by a light inextensible thread of length l is projected horizontally from its lowest poditiin
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