A particle is suspended from a fixed point and projected horizontally with velocity √7gl/2.the string will slack through an angle find that angle.

Question

Vikas TU · Answer

in y direction from neton’s thord law of eqn., (vy)^2 = ( √7gl/2)sinthetha – 0.5gt^2 and (vx)^2 = ( √7gl/2)costhetha – gt Now put vx and vy = 0 and solve for thetha and t.

Khu · Answer

A particle suspend by a light inextensible thread of length l is projected horizontally from its lowest poditiin

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A particle is suspended from a fixed point and projected horizontally with velocity √7gl/2.the string will slack through an angle find that angle.

A particle is suspended from a fixed point and projected horizontally with velocity √7gl/2.the string will slack through an angle find that angle.

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A particle is suspended from a fixed point and projected horizontally with velocity √7gl/2.the string will slack through an angle find that angle.

A particle is suspended from a fixed point and projected horizontally with velocity √7gl/2.the string will slack through an angle find that angle.

2 Answers

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