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A particle is projected with velocity v along x axis. The deceleration on the particle is directly proportional to the square of distance a = b*x² . the dustance at which particle stop is (Answer is (3v/2b)^1/3)

Simran Khan , 9 Years ago
Grade 12th pass
anser 1 Answers
Vikas TU

Last Activity: 9 Years ago

a = vdv/dx = b*x^2 
vdv = (b*x^2)dx
Integerating both sides,
 
v^2/2 = b*x^3/3
x = 3v/2b)^1/3
 
is the answer.
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