Mechanics> A particle is projected up with an initia...

A particle is projected up with an initial velocity of 80 feet per second the ball will be at the height of 96 feet from the ground after how much second

Prisha , 8 Years ago

Grade 11

1 Answers

Deepak Kumar

Initial Velovity = U₀ = 80feet/second.

Height = H = 80 feet.

Acceleration due to gravity = g = 32 feet/s².

Using kinematic 2^nd equation.

H = U₀t + at²/2.

96 = 80t -32t²/2.

t²-5t +6 =0.

Solving above equation We get

t = 2seconds and 3 seconds.

It means when particle goes to upward direction then at 2seconds it is at 96 feet height.

and at the returing time at 3seconds its height is 96feet.

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Last Activity: 8 Years ago

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Mechanics> A particle is projected up with an initia...

A particle is projected up with an initial velocity of 80 feet per second the ball will be at the height of 96 feet from the ground after how much second

Prisha , 8 Years ago

Deepak Kumar

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