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A particle is projected from the mid-point of the line joining two fixed particles each of mass m. If the separation between the fixed particles is l, the minimum velocity of projection of the particle so as to escape is equal to

Rushil , 6 Years ago
Grade 12
anser 1 Answers
Vikas TU

Last Activity: 5 Years ago

Dear student 
gravitational potential at the mid-point P,
V = V1 + V2 
V = -4Gm/l 
U = -4Gmm0 / l 
When it is projected with a speed v, it just escapes to infinity, and the potential and kinetic energy will become zero.
KE + PE = 0 
v = 2sqty(2Gm/l)
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