A particle is projected from the ground at an angle 60° with the horizontal that speed u= 20m/s find the radius of curvature of the path of the particle when its velocity makes an angle of 30° with horizontal

Question

Vikas TU · Answer

R = (1 + (dy/dx)^2)^3/2/|d^2y/dx^2| use trajectory equation, y = xtanthetha – gx^2/2u^2costhetha. find dy/dx and d2y/dx2. respecively and substitute in R.

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A particle is projected from the ground at an angle 60° with the horizontal that speed u= 20m/s find the radius of curvature of the path of the particle when its velocity makes an angle of 30° with horizontal

A particle is projected from the ground at an angle 60° with the horizontal that speed u= 20m/s find the radius of curvature of the path of the particle when its velocity makes an angle of 30° with horizontal

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A particle is projected from the ground at an angle 60° with the horizontal that speed u= 20m/s find the radius of curvature of the path of the particle when its velocity makes an angle of 30° with horizontal

A particle is projected from the ground at an angle 60° with the horizontal that speed u= 20m/s find the radius of curvature of the path of the particle when its velocity makes an angle of 30° with horizontal

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