A particle is projected from the ground at an angle 60° with the horizontal that speed u= 20m/s find the radius of curvature of the path of the particle when its velocity makes an angle of 30° with horizontal
Madhav , 8 Years ago
Grade 11
1 Answers
Vikas TU
Last Activity: 8 Years ago
R = (1 + (dy/dx)^2)^3/2/|d^2y/dx^2|
use trajectory equation,
y = xtanthetha – gx^2/2u^2costhetha.
find dy/dx and d2y/dx2. respecively and substitute in R.