a particle is projected from horizontal ground with speed of 20m/s at a certain angle with the horizontal ,so that it just clears two vertical walls of equal heights 10 mwhich are at horizontal distance of 20 m from each other .Find the time taken by the particle to pass between the two walls.

Question

Abhinav · Answer

take two points in space (x,10) and (x+20 ,10) put these points in equation of trajectory of projectile and divide both expressions obtained

equation of trajectory of projectile is
y = (x- x²/2R)tan $\Theta$

you will get value of X. put it again in equation to get value of $\Theta$ .

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a particle is projected from horizontal ground with speed of 20m/s at a certain angle with the horizontal ,so that it just clears two vertical walls of equal heights 10 mwhich are at horizontal distance of 20 m from each other .Find the time taken by the particle to pass between the two walls.

a particle is projected from horizontal ground with speed of 20m/s at a certain angle with the horizontal ,so that it just clears two vertical walls of equal heights 10 mwhich are at horizontal distance of 20 m from each other .Find the time taken by the particle to pass between the two walls.

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a particle is projected from horizontal ground with speed of 20m/s at a certain angle with the horizontal ,so that it just clears two vertical walls of equal heights 10 mwhich are at horizontal distance of 20 m from each other .Find the time taken by the particle to pass between the two walls.

a particle is projected from horizontal ground with speed of 20m/s at a certain angle with the horizontal ,so that it just clears two vertical walls of equal heights 10 mwhich are at horizontal distance of 20 m from each other .Find the time taken by the particle to pass between the two walls.

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