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Grade 10General Physics

A particle is moving on a circle of radius 1 km with constant speed of 10π m/s. Find the change in velocity vector of particle in a time duration of 1 second ( in m/s).

Profile image of Ritik Raj
9 Years agoGrade 10
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1 Answer

Profile image of Vikas TU
9 Years ago
As we all know that change in velocity = Vfinal - Vinitial
As the motion is circular Initial velocity = -v
Then change in velocity = 2v
Acceleration = 2v/t
                       = 2v^2/(pi*r)
                       = (2 x 100 xpi*pi)/(pi*1000)
                      = 22/35 m/s^2
A = change in velocity/time
22/35 = change in velocity