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A particle is moving in positive x-direction with initial velocity of 10 m/s and uniform retardation such that it reaches the initial position after 10s.The distance transversed by the particle in 6s is ?
A particle is moving in positive x-direction with initial velocity of 10 m/s and uniform retardation such that it reaches the initial position after 10s.The distance transversed by the particle in 6s is ?

```
2 years ago

Eshan
2095 Points
```							Dear student,From$s=ut+\dfrac{1}{2}at^2=0\implies t=-\dfrac{2u}{a}$$\implies a=-2m/s^2$Hence$s(t=6s)=ut+\dfrac{1}{2}at^2=60-36=24m$
```
2 years ago
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