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Grade 10General Physics

A particle is moving in positive x-direction with initial velocity of 10 m/s and uniform retardation such that it reaches the initial position after 10s.The distance transversed by the particle in 6s is ?

Profile image of SAMBHAV MISHRA
7 Years agoGrade 10
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1 Answer

Profile image of Eshan
7 Years ago
Dear student,

Froms=ut+\dfrac{1}{2}at^2=0\implies t=-\dfrac{2u}{a}
\implies a=-2m/s^2

Hences(t=6s)=ut+\dfrac{1}{2}at^2=60-36=24m