Flag General Physics> A particle is moving in positive x – dire...
question mark

A particle is moving in positive x– direction with initial velocity of 10 m/s and uniform retardation such that it reaches the initial position after 10s. The distance traversed by the particle in 6 seconds is

(A) 24 m(B) 25 m(C) 26 m(D) 27 m

Krishnansu , 8 Years ago
Grade 9
anser 1 Answers
Aaryan Gupta

Last Activity: 8 Years ago

It is clear from the question that the particle stops and reverts its path after 5s. Therefore, to find the retardation we use,
v=u+at  ,  i.e.  ,  0=10 – a*5 ,  which gives us a=2.
Now distance travelled in 5s => s=ut+1/2at​2  , i.e. ,  s=10*5 – 1/2*2*5​2       , which gives s=25m    
After 5s velocity becomes 0 and particle starts to move in negative x-direction with the acceleration of 2.
Therefore, distance travelled in the 6th second => s=0*1 + 1/2*2*1​2         which gives us s=1m
Hence, total distance travelled = 25+1= 26m. So, the (C) option is correct.                               ​
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments