A particle is moving eastwards with a velocity of 5m/s.In 10 seconds,the velocity changes to 5m/s northwards. Find the average acceleration of the particle in this time interval and also sketch the vector diagram..
Swikar Pokhrel , 5 Years ago
Grade 11
1 Answers
Arun
Last Activity: 5 Years ago
Intial velocity=v1= 5m/seast wards ^||^ then after time t=10sec || towards north 5m/s v2 =5m/s north wards .⇒⇒⇒⇒⇒⇒| towards east 5m/s Vresultant = √v1²+v2² =√25+25 =5 √2
acceleration a=velocity/time = 5√2/10 =√2/2 × √2/√2 =1/√2 towards n-w
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