A particle is moving at a speed of 12m/s on a circle of radius r.If the speed of the particle is increased to 15m/s in 2 sec,what is the angular acceleration produced?

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Khimraj · Answer

w1 = v1/r = 12/r w2 = v2/r = 15/r angular acceleration = (w2 – w1)/t = 3/2r If value of radius is given then put in place of r Hope it clears...................

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A particle is moving at a speed of 12m/s on a circle of radius r.If the speed of the particle is increased to 15m/s in 2 sec,what is the angular acceleration produced?

A particle is moving at a speed of 12m/s on a circle of radius r.If the speed of the particle is increased to 15m/s in 2 sec,what is the angular acceleration produced?

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A particle is moving at a speed of 12m/s on a circle of radius r.If the speed of the particle is increased to 15m/s in 2 sec,what is the angular acceleration produced?

A particle is moving at a speed of 12m/s on a circle of radius r.If the speed of the particle is increased to 15m/s in 2 sec,what is the angular acceleration produced?

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