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a particle is dropped from the top of a very high towe then the distance covered in the fifth second of its fall is?

a particle is dropped from the top of a very high towe then the distance covered in the fifth second of its fall is?

Grade:11

1 Answers

yash
25 Points
8 years ago
As you go higher from the earth surface the gravity shows some devitation from its acceleration. As you have not provided any information regarding that i will assume g = 9.8m/s2 .
We will use the third euation of motion...s = ut+ ½ at2...As the initially it is droped initial velocity (u)=0
So the equation becomes S = ½ at2 Now to find the distance traveled in the 5 the second We will subtract total distance travelled in in 5 second – total distance travelled in 4 seconds so you get distance travelled in 5th second.
S5 = ½ x 9.8 x 5 x 5 =122.4 m
S4 = ½ x 9.8 x 4 x4 = 76.4 m  
S5-S4= 46 m this the answer i Got 

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