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        A particle executes SHM along the x-axis and has the center of oscillation at x = A. The angular frequency of the oscillations is ω and amplitude is A. Initially, the particle is at rest at the origin. Which of the following represents the equation of position of the particle ? (1) x = –A sin ωt(2) x = A sin ωt(3) x = -A + A cos ωt(4) x = A – Acosωt
2 years ago

Eshan
2095 Points
							Dear student,Equation of SHM with center at origin isBut if the center is shifted by A, the equation becomesNow the particle starts from x=0.Hence at t=0, x=0Hence

one year ago
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• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions