MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        
A particle executes SHM along the x-axis and has the center of oscillation at x = A. The angular frequency of the oscillations is ω and amplitude is A. Initially, the particle is at rest at the origin. Which of the following represents the equation of position of the particle ?
 
(1) x = –A sin ωt
(2) x = A sin ωt
(3) x = -A + A cos ωt
(4) x = A – Acosωt
2 years ago

Answers : (1)

Eshan
askIITians Faculty
2095 Points
							Dear student,

Equation of SHM with center at origin isx=A sin(\omega t+\phi_0)

But if the center is shifted by A, the equation becomesx=A+A sin(\omega t+\phi_0)
Now the particle starts from x=0.

Hence at t=0, x=0

\implies 0=A + Asin\phi_0
\implies sin\phi_0\implies \phi_0=\dfrac{3\pi}{2}
Hencex=A-Acos\omega t
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 18 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details