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A man throws ball to maximum horizontal distance of 80m. Calculate maximum height reached..?
We know that R = u2 * Sin 2θ / g.As, the range is maximum, so, θ = 450So, 80 = u2 /g.Now, H = height reached by ball = u2 Sin2θ / 2g.Putting value of θ = 450 , u2 / g = 80, we getH = 80/4 = 20m
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