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A man of mass m moves with a constant speed on a plank of mass M ansd length L kept initially at rest on a frictionaless horizontal surface, from one end to the other in time t. the speed of plank relative to ground while man is moving is: L/t(M/m) L/t(m/(M+m)) L/t(M/(M-m)) none of these

Ujjwal Nath , 8 Years ago
Grade 11
anser 2 Answers
Vikas TU

Last Activity: 8 Years ago

Let x be the distance covered by planck then,
Mx = m(L-x)
Solving for x,
(M+m)x = mL
x = mL / (M+m) .
Speed of planck = > x/t =  > mL / (M+m)t . 
i think none of these.

Annu

Last Activity: 7 Years ago

Let the distance moved by the plank be x.So the distance that the man will move is L - x.Applying Conservation of Linear Momentum,Mx = m(L - x)Mx = mL - mxMx + mx = mLx(M + m) = mLx = mL / (M + m)Distance moved by the plank in T seconds is mL/( M + m).Speed = Distance ÷ TimeSpeed = mL/ [ (M + m)T]

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