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`        A man is weighing 160 pounds stans on the floor of elevator. What force will be exerted on the floor what if it 1- decends With a uniform acceleration of 1 ft/sec2 2-  Ascending with a uniform acceleration of 1ft/sec2.`
5 months ago

## Answers : (4)

Pooja
124 Points
```							g = 32.2ft /s2force exerted on the floor =N➡️when lift decendsN = m(g-a)   =160(32.2-1)   = 4976 pound.ft/sec2➡️when lift ascendsN = m(g+a)     =160(32.2+1)     = 5132 pound.ft/sec2
```
5 months ago
yohib ahmed
27 Points
```							g = 32.2ft /s2?? please ask me why g = 32.2ft /s2 you put here? please ask me why g = 32.2ft /s2 you put here?
```
5 months ago
yohib ahmed
27 Points
```							 g = 32.2ft /s2?? please ask me why g = 32.2ft /s2 you put here? please ask me why g = 32.2ft /s2 you put here?  I got it. You convert m into ft 9.8x3.28
```
5 months ago
Khimraj
3008 Points
```							 when lift decendsN = m(g-a)   =160(32.2-1)   = 4976 pound.ft/sec2when lift ascendsN = m(g+a)     =160(32.2+1)     = 5132 pound.ft/sec2
```
5 months ago
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions