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A man is walking in east direction with velocity of 3 km/hr. Rain appears to him falling vertically at 4 km/hr. Find the velocity of rain and the angle it is deducing with the horizontal.
Please answer with proper explainations.

Aabha Misra , 7 Years ago
Grade 12th pass
anser 2 Answers
Kashinath Patekar
Since rain appears to fall vertically to the man, that means, the horizontal component of rain's velocity is same as the velocity of man(which is entirely horizontal with respect to ground, and equal to 3 km/hr).    
Hence, Vx(rain)=  3 km/hr  (Eqn 1)   
Also, the velocity of rain in vetical direction wrt man is 4 km/hr. Since man is not moving in vertical direction, thay means, the velocity of rain wrt ground in vertical direction is 4 km/hr too.
Hence, Vy(rain)=4 km/hr. (Eqn 2) 
From Eqns 1 and 2, the resultant velocity of rain
 Vrain=  ✓(32 + 42)  = ✓25 = 5 km/hr. 
Let @ be the angle between rain's velocity and horizontal.
tan @= 4/3
thus, @= tan-1 4/3= 53°
I hope that helps. :)
Last Activity: 7 Years ago
Khimraj
velocity of rain with respect to man = \sqrt{3^{2} + 4^{2}} = 5 m/s
angle with horizontal
tan\Theta = 4/3
so \Theta = tan-14/3 = 53o
Hope it clears.
Last Activity: 7 Years ago
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