. A long spring is stretched by 2cm. Its potential energy is V. If the spring is stretched by 10cm, its potential energy would be A. V/25 B. V/5 C. 5V D. 25V
aditya kashyap , 11 Years ago
Grade upto college level
1 Answers
Unni
Last Activity: 6 Years ago
potential energy of spring =1/2kx^2
Therefore when x=2 ,PE=1/2k(2^2)=2k
Similarly x=10,PE=1/2k(10^2)=50k=25×2k
Given 2k=U then 25×2k=25U (I given v=u)
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