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AJFET hasIDSS= 20 mA. At what gate source voltage (VGS)will it`s drain current be 5 mA, it`s pinch offvoltage is 4.2 V

Anisha Kumari , 7 Years ago
Grade 12th pass
anser 1 Answers
Khimraj

Last Activity: 7 Years ago

Formula of drain current
ID = IDSS(1 – VGS/VP)2
Given that ID = 5mA, IDSS = 20mA, VP= 4.2 V
ID/IDSS = (1 – VGS/4.2)2
¼ = (1 – VGS/4.2)2
½ = (1 – VGS/4.2)
0.5*4.2 = 4.2 – VGS
VGS= 4.2 – 2.1 = 2.1V.
Hope it clears. If you like answer then please approve it.

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