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`        A  JFET has  IDSS= 20 mA. At what gate source voltage (VGS)  will it`s drain current be 5 mA, it`s pinch off  voltage is 4.2 V`
11 months ago

Khimraj
2571 Points
```							Formula of drain currentID = IDSS(1 – VGS/VP)2Given that ID = 5mA, IDSS = 20mA, VP= 4.2 VID/IDSS = (1 – VGS/4.2)2¼ = (1 – VGS/4.2)2½ = (1 – VGS/4.2)0.5*4.2 = 4.2 – VGSVGS= 4.2 – 2.1 = 2.1V.Hope it clears. If you like answer then please approve it.
```
11 months ago
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