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Grade: 12th Pass
        
a jeep starts from rest with constant acc of 4 m/s^2. at the same time a car travels with a comstant speed of 36 km/hrs
over takes and passes the jeep. how far beyond th starting point the jeep overtake the car?
10 months ago

Answers : (2)

Saurabh Koranglekar
askIITians Faculty
2728 Points
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10 months ago
Khimraj
3008 Points
							
acceleration of jeep a = 4 m/s2
speed of car v = 36 km/hr = 36*5/18 = 10m/s
to overtake distance travelled by both should be same.
so
½*4*t2 = 10*t
2t = 10
t = 5 sec
distance covered = 10*5 = 50m
Hope it clears...................
10 months ago
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