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Grade 12th PassGeneral Physics

a jeep starts from rest with constant acc of 4 m/s^2. at the same time a car travels with a comstant speed of 36 km/hrs
over takes and passes the jeep. how far beyond th starting point the jeep overtake the car?

Profile image of Saiba Muhammed
7 Years agoGrade 12th Pass
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2 Answers

Profile image of Saurabh Koranglekar
7 Years ago
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Profile image of Khimraj
7 Years ago
acceleration of jeep a = 4 m/s2
speed of car v = 36 km/hr = 36*5/18 = 10m/s
to overtake distance travelled by both should be same.
so
½*4*t2 = 10*t
2t = 10
t = 5 sec
distance covered = 10*5 = 50m
Hope it clears...................