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`        a jeep starts from rest with constant acc of 4 m/s^2. at the same time a car travels with a comstant speed of 36 km/hrsover takes and passes the jeep. how far beyond th starting point the jeep overtake the car?`
one year ago

Saurabh Koranglekar
3431 Points
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one year ago
Khimraj
3008 Points
```							acceleration of jeep a = 4 m/s2speed of car v = 36 km/hr = 36*5/18 = 10m/sto overtake distance travelled by both should be same.so½*4*t2 = 10*t2t = 10t = 5 secdistance covered = 10*5 = 50mHope it clears...................
```
one year ago
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions